1   For each of the following subsets of F3\mathbf{F}^3, determine whether it is a subspace of F3\mathbf{F}^3.
(a)   {(x1,x2,x3)F3:x1+2x2+3x3=0}\{ (x_1,x_2,x_3) \in \mathbf{F}^3: x_1 + 2x_2 + 3x_3 = 0 \}
(b)   {(x1,x2,x3)F3:x1+2x2+3x3=4}\{ (x_1,x_2,x_3) \in \mathbf{F}^3: x_1 + 2x_2 + 3x_3 = 4 \}
(c)   {(x1,x2,x3)F3:x1x2x3=0}\{ (x_1,x_2,x_3) \in \mathbf{F}^3: x_1x_2x_3 = 0 \}
(d)   {(x1,x2,x3)F3:x1=5x3}\{ (x_1,x_2,x_3) \in \mathbf{F}^3: x_1 = 5x_3 \}

Solution

Recall that three conditions are necessary and sufficient to show that a subset UU of a vector space VV over a field F\mathbf{F} is a subspace:

  1. additive identity

0U0 \in U

  1. closed under addition

u,wU    u+wUu, w \in U \implies u + w \in U

  1. closed under scalar multiplication

aFaU    auUa \in \mathbf{F} \land a \in U \implies au \in U

(a)   U={(x1,x2,x3)F3:x1+2x2+3x3=0}U = \{ (x_1,x_2,x_3) \in \mathbf{F}^3: x_1 + 2x_2 + 3x_3 = 0 \}

Clearly 0=(0,0,0)U0 = (0,0,0) \in U as 0+2×0+3×0=00 + 2 \times 0 + 3 \times 0 = 0 so 1. additive identity holds.

Let u=(u1,u2,u3),w=(w1,w2,w3)Uu = (u_1, u_2, u_3), w = (w_1, w_2, w_3) \in U. Then

(u1+w1)+2(u2+w2)+3(u3+w3)=(u1+2u2+3u3)+(w1+2w2+3w3)=0+0=0,(u_1 + w_1) + 2(u_2 + w_2) + 3(u_3 + w_3) \\ = (u_1 + 2u_2 + 3u_3) + (w_1 + 2w_2 + 3w_3) = 0 + 0 = 0,

so 2. closed under addition holds.

Let aFa \in \mathbf{F}. Then

(au1)+2(au2)+3(au3)=a(u1+2u2+3u3)=a0=0,(au_1) + 2(au_2) + 3(au_3) = a (u_1 + 2u_2 + 3u_3) = a \cdot 0 = 0,

so au=(au1,au2,au3)Uau = (au_1, au_2, au_3) \in U, so 3. closed under scalar multiplication holds.

We conclude that UU is a subspace. \quad \square

(b)   U={(x1,x2,x3)F3:x1+2x2+3x3=4}U = \{ (x_1,x_2,x_3) \in \mathbf{F}^3: x_1 + 2x_2 + 3x_3 = 4 \}

UU is not a subspace because it doesn't contain 00. \quad \square

(c)   U={(x1,x2,x3)F3:x1x2x3=0}U = \{ (x_1,x_2,x_3) \in \mathbf{F}^3: x_1x_2x_3 = 0 \}

UU is not a subspace because it isn't closed under addition. (1,0,1)U(1, 0, 1) \in U and (0,1,0)U(0,1,0) \in U but (1,0,1)+(0,1,0)=(1,1,1)U(1,0,1) + (0,1,0) = (1,1,1) \notin U. \quad \square

(d)   U={(x1,x2,x3)F3:x1=5x3}U = \{ (x_1,x_2,x_3) \in \mathbf{F}^3: x_1 = 5x_3 \}

Clearly 0U0 \in U so 1. additive identity holds.

If u=(u1,u2,u3),w=(w1,w2,w3)Uu = (u_1, u_2, u_3), w = (w_1, w_2, w_3) \in U. Then

u1+w1=5u3+5w3=5(u3+w3)=50=0,u_1 + w_1 = 5u_3 + 5w_3 = 5(u_3 + w_3) = 5 \cdot 0 = 0,

so 2. closed under addition holds.

If aFa \in \mathbf{F} then

au1=a(5u3)=5(au3),au_1 = a(5u_3) = 5(au_3),

so auFau \in \mathbf{F}, and therefore 3. closed under scalar multiplication holds.

We conclude that UU is a subspace. \quad \square


2   Verify the following assertions about subspaces:

(a)\text{(a)} \> If bFb \in \mathbf{F}, then

{(x1,x2,x3,x4)F4:x3=5x4+b}\{(x_1,x_2,x_3,x_4) \in \mathbf{F}^4: x_3 = 5x_4 + b\}

is a subspace of F4\mathbf{F}^4 if and only if b=0b=0.

(b)\text{(b)} \> The set of continuous real-valued functions on the interval [0,1][0,1] is a subspace of R[0,1]\mathbf{R}^{[0,1]}.

(c)\text{(c)} \> The set of differentiable real-valued functions on R\mathbf{R} is a subspace of RR\mathbf{R}^\mathbf{R}.

(d)\text{(d)} \> The set of differentiable real-valued functions ff on the interval (0,3)(0,3) such that f(2)=bf'(2) = b is a subspace of R(0,3)\mathbf{R}^{(0,3)} if and only if b=0b=0.

(e)\text{(e)} \> The set of all sequences of complex numbers with limit 00 is a subspace of C\mathbf{C}^\infty.


3   Show that the set of differentiable real-valued functions ff on the interval (4,4)(-4,4) such that f(1)=3f(2)f'(-1)=3f(2) is a subspace of R(4,4)\mathbf{R}^{(-4,4)}.


4   Suppose bRb \in \mathbf{R}. Show that the set of continuous real-valued functions ff on the interval [0,1][0,1] such that 01f=b\int_0^1 f = b is a subspace of R[0,1]\mathbf{R}^{[0,1]} if and only if b=0b=0.


5   Is R2\mathbf{R}^2 a subspace of the complex vector space C2\mathbf{C}^2?


6   (a) Is {(a,b,c)R3:a3=b3}\{(a,b,c) \in \mathbf{R}^3: a^3 = b^3\} a subspace of R3\mathbf{R}^3?
(b) Is {(a,b,c)C3:a3=b3}\{(a,b,c) \in \mathbf{C}^3: a^3=b^3\} a subspace of C3\mathbf{C}^3?


7   Prove or give a counterexample: If UU is a nonempty subset of R2\mathbf{R}^2 such that UU is closed under addition and under taking additive inverses (meaning uU-u \in U whenever uUu \in U), then UU is not a subspace of R2\mathbf{R}^2.


8   Give an example of a nonempty subset UU of R2\mathbf{R}^2 such that UU is closed under scalar multiplication, but UU is not a subspace of R2\mathbf{R}^2.


9   A function f:RRf: \mathbf{R} \to \mathbf{R} is called periodic if there exists a positive number pp such that f(x)=f(x+p)f(x) = f(x+p) for all xRx \in \mathbf{R}. Is the set of periodic functions from R\mathbf{R} to R\mathbf{R} a subspace of RR\mathbf{R}^{\mathbf{R}}? Explain.


10   Suppose V1V_1 and V2V_2 are subspaces of VV. Prove that the intersection V1V2V_1 \cap V_2 is a subspace of VV.


11   Prove that the intersection of every collection of subspaces of VV is a subspace of VV.


12   Prove that the union of two subspaces of VV is a subspace of VV if and only if one of the subspaces is contained in the other.


13   Prove that the union of three subspaces of VV is a subspace of VV if and only if one of the subspaces contains the other two.

This exercise is surprisingly harder than Exercise 12, possibly because this exercise is not true if we replace F\mathbf{F} with a field containing only two elements.


14   Suppose

U={(x,x,2x)F3:xF}andW={(x,x,2x)F3:xF}.U = \{(x,-x,2x)\in \mathbf{F}^3: x \in \mathbf{F}\} \quad \text{and} \quad W = \{(x,x,2x) \in \mathbf{F}^3:x \in F\}.

Describe U+WU + W using symbols, and also give a description of U+WU+W that uses no symbols.


15   Suppose UU is a subspace of VV. What is U+UU + U?


16   Is the operation of addition on the subspaces of VV commutative? In other words, if UU and WW are subspaces of VV, is U+W=W+UU + W = W + U?


17   Is the operation of addition on the subspaces of VV associative? In other words, if V1V_1, V2V_2, V3V_3 are subspaces of VV, is

(V1+V2)+V3=V1+(V2+V3)?(V_1 + V_2) + V_3 = V_1 + (V_2 + V_3)?


18   Does this operation of addition on the subspaces of VV have an additive identity? Which subspaces have additive inverses?


19   Prove or give a counterexample: If V1V_1, V2V_2, UU are subspaces of VV such that

V1+U=V2+U,V_1 + U = V_2 + U,

then V1=V2V_1 = V_2.


20   Suppose

U={(x,x,y,y):F4:x,yF}.U = \{ (x,x,y,y): \in \mathbf{F}^4: x,y \in \mathbf{F} \}.

Find a subspace WW of F4\mathbf{F}^4 such that F4=UW\mathbf{F}^4 = U \oplus W.


21   Suppose

U={(x,y,x+y,xy,2x):F5:x,yF}.U = \{ (x,y,x+y,x-y,2x): \in \mathbf{F}^5: x,y \in \mathbf{F} \}.

Find a subspace WW of F5\mathbf{F}^5 such that F5=UW\mathbf{F}^5 = U \oplus W.


22   Suppose

U={(x,y,x+y,xy,2x)F5:x,yF}.U = \{(x,y,x+y,x-y,2x)\in \mathbf{F}^5: x,y\in\mathbf{F}\}.

Find three subspaces W1W_1, W2W_2, W3W_3 of F5\mathbf{F}^5, none of which equals {0}\{0\}, such that F5=UW1W2W3\mathbf{F}^5 = U \oplus W_1 \oplus W_2 \oplus W_3.


23   Prove or give a counterexample: If V1V_1, V2V_2, UU are subspaces of VV such that

V=V1UandV=V2U,V = V_1 \oplus U \quad \text{and} \quad V = V_2 \oplus U,

then V1=V2V_1 = V_2.

Hint: When trying to discover whether a conjecture in linear algebra is true or false, it is often useful to start by experimenting in F2\mathbf{F}^2.


24   A function f:RRf: \mathbf{R} \to \mathbf{R} is called even if

f(x)=f(x)f(-x) = f(x)

for all xRx \in \mathbf{R}. A function f:RRf: \mathbf{R} \to \mathbf{R} is called odd if

f(x)=f(x)f(-x) = -f(x)

for all xRx \in \mathbf{R}. Let VeV_\text{e} denote the set of real-valued even functions on R\mathbf{R} and let VoV_\text{o} denote the set of real-valued odd functions on R\mathbf{R}. Show that RR=VeVo\mathbf{R}^\mathbf{R} = V_\text{e} \oplus V_\text{o}.

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